Optimal. Leaf size=198 \[ \frac{e \sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^5 (-3 a B e+A b e+2 b B d)}{6 b^4}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^4 (b d-a e) (-3 a B e+2 A b e+b B d)}{5 b^4}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^3 (A b-a B) (b d-a e)^2}{4 b^4}+\frac{B e^2 \sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^6}{7 b^4} \]
[Out]
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Rubi [A] time = 0.571259, antiderivative size = 198, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.061 \[ \frac{e \sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^5 (-3 a B e+A b e+2 b B d)}{6 b^4}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^4 (b d-a e) (-3 a B e+2 A b e+b B d)}{5 b^4}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^3 (A b-a B) (b d-a e)^2}{4 b^4}+\frac{B e^2 \sqrt{a^2+2 a b x+b^2 x^2} (a+b x)^6}{7 b^4} \]
Antiderivative was successfully verified.
[In] Int[(A + B*x)*(d + e*x)^2*(a^2 + 2*a*b*x + b^2*x^2)^(3/2),x]
[Out]
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Rubi in Sympy [A] time = 38.1738, size = 221, normalized size = 1.12 \[ \frac{B \left (2 a + 2 b x\right ) \left (d + e x\right )^{3} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}}{14 b e} + \frac{\left (2 a + 2 b x\right ) \left (d + e x\right )^{2} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}} \left (7 A b e - 3 B a e - 4 B b d\right )}{84 b^{2} e} - \frac{\left (a e - b d\right ) \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{5}{2}} \left (7 A b e - 3 B a e - 4 B b d\right )}{105 b^{4}} + \frac{\left (2 a + 2 b x\right ) \left (a e - b d\right )^{2} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}} \left (7 A b e - 3 B a e - 4 B b d\right )}{168 b^{4} e} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(e*x+d)**2*(b**2*x**2+2*a*b*x+a**2)**(3/2),x)
[Out]
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Mathematica [A] time = 0.206633, size = 233, normalized size = 1.18 \[ \frac{x \sqrt{(a+b x)^2} \left (35 a^3 \left (4 A \left (3 d^2+3 d e x+e^2 x^2\right )+B x \left (6 d^2+8 d e x+3 e^2 x^2\right )\right )+21 a^2 b x \left (5 A \left (6 d^2+8 d e x+3 e^2 x^2\right )+2 B x \left (10 d^2+15 d e x+6 e^2 x^2\right )\right )+21 a b^2 x^2 \left (2 A \left (10 d^2+15 d e x+6 e^2 x^2\right )+B x \left (15 d^2+24 d e x+10 e^2 x^2\right )\right )+b^3 x^3 \left (7 A \left (15 d^2+24 d e x+10 e^2 x^2\right )+4 B x \left (21 d^2+35 d e x+15 e^2 x^2\right )\right )\right )}{420 (a+b x)} \]
Antiderivative was successfully verified.
[In] Integrate[(A + B*x)*(d + e*x)^2*(a^2 + 2*a*b*x + b^2*x^2)^(3/2),x]
[Out]
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Maple [B] time = 0.012, size = 304, normalized size = 1.5 \[{\frac{x \left ( 60\,{b}^{3}B{e}^{2}{x}^{6}+70\,{x}^{5}A{b}^{3}{e}^{2}+210\,{x}^{5}B{e}^{2}a{b}^{2}+140\,{x}^{5}B{b}^{3}de+252\,{x}^{4}Aa{b}^{2}{e}^{2}+168\,{x}^{4}A{b}^{3}de+252\,{x}^{4}B{e}^{2}{a}^{2}b+504\,{x}^{4}Ba{b}^{2}de+84\,{x}^{4}B{b}^{3}{d}^{2}+315\,{x}^{3}A{a}^{2}b{e}^{2}+630\,{x}^{3}Aa{b}^{2}de+105\,{x}^{3}A{b}^{3}{d}^{2}+105\,{x}^{3}B{e}^{2}{a}^{3}+630\,{x}^{3}B{a}^{2}bde+315\,{x}^{3}Ba{b}^{2}{d}^{2}+140\,{x}^{2}A{a}^{3}{e}^{2}+840\,{x}^{2}A{a}^{2}bde+420\,{x}^{2}A{d}^{2}a{b}^{2}+280\,{x}^{2}B{a}^{3}de+420\,{x}^{2}B{a}^{2}b{d}^{2}+420\,xA{a}^{3}de+630\,xA{d}^{2}{a}^{2}b+210\,xB{a}^{3}{d}^{2}+420\,A{d}^{2}{a}^{3} \right ) }{420\, \left ( bx+a \right ) ^{3}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{{\frac{3}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(e*x+d)^2*(b^2*x^2+2*a*b*x+a^2)^(3/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(B*x + A)*(e*x + d)^2,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.26717, size = 323, normalized size = 1.63 \[ \frac{1}{7} \, B b^{3} e^{2} x^{7} + A a^{3} d^{2} x + \frac{1}{6} \,{\left (2 \, B b^{3} d e +{\left (3 \, B a b^{2} + A b^{3}\right )} e^{2}\right )} x^{6} + \frac{1}{5} \,{\left (B b^{3} d^{2} + 2 \,{\left (3 \, B a b^{2} + A b^{3}\right )} d e + 3 \,{\left (B a^{2} b + A a b^{2}\right )} e^{2}\right )} x^{5} + \frac{1}{4} \,{\left ({\left (3 \, B a b^{2} + A b^{3}\right )} d^{2} + 6 \,{\left (B a^{2} b + A a b^{2}\right )} d e +{\left (B a^{3} + 3 \, A a^{2} b\right )} e^{2}\right )} x^{4} + \frac{1}{3} \,{\left (A a^{3} e^{2} + 3 \,{\left (B a^{2} b + A a b^{2}\right )} d^{2} + 2 \,{\left (B a^{3} + 3 \, A a^{2} b\right )} d e\right )} x^{3} + \frac{1}{2} \,{\left (2 \, A a^{3} d e +{\left (B a^{3} + 3 \, A a^{2} b\right )} d^{2}\right )} x^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(B*x + A)*(e*x + d)^2,x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \left (A + B x\right ) \left (d + e x\right )^{2} \left (\left (a + b x\right )^{2}\right )^{\frac{3}{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(e*x+d)**2*(b**2*x**2+2*a*b*x+a**2)**(3/2),x)
[Out]
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GIAC/XCAS [A] time = 0.318916, size = 582, normalized size = 2.94 \[ \frac{1}{7} \, B b^{3} x^{7} e^{2}{\rm sign}\left (b x + a\right ) + \frac{1}{3} \, B b^{3} d x^{6} e{\rm sign}\left (b x + a\right ) + \frac{1}{5} \, B b^{3} d^{2} x^{5}{\rm sign}\left (b x + a\right ) + \frac{1}{2} \, B a b^{2} x^{6} e^{2}{\rm sign}\left (b x + a\right ) + \frac{1}{6} \, A b^{3} x^{6} e^{2}{\rm sign}\left (b x + a\right ) + \frac{6}{5} \, B a b^{2} d x^{5} e{\rm sign}\left (b x + a\right ) + \frac{2}{5} \, A b^{3} d x^{5} e{\rm sign}\left (b x + a\right ) + \frac{3}{4} \, B a b^{2} d^{2} x^{4}{\rm sign}\left (b x + a\right ) + \frac{1}{4} \, A b^{3} d^{2} x^{4}{\rm sign}\left (b x + a\right ) + \frac{3}{5} \, B a^{2} b x^{5} e^{2}{\rm sign}\left (b x + a\right ) + \frac{3}{5} \, A a b^{2} x^{5} e^{2}{\rm sign}\left (b x + a\right ) + \frac{3}{2} \, B a^{2} b d x^{4} e{\rm sign}\left (b x + a\right ) + \frac{3}{2} \, A a b^{2} d x^{4} e{\rm sign}\left (b x + a\right ) + B a^{2} b d^{2} x^{3}{\rm sign}\left (b x + a\right ) + A a b^{2} d^{2} x^{3}{\rm sign}\left (b x + a\right ) + \frac{1}{4} \, B a^{3} x^{4} e^{2}{\rm sign}\left (b x + a\right ) + \frac{3}{4} \, A a^{2} b x^{4} e^{2}{\rm sign}\left (b x + a\right ) + \frac{2}{3} \, B a^{3} d x^{3} e{\rm sign}\left (b x + a\right ) + 2 \, A a^{2} b d x^{3} e{\rm sign}\left (b x + a\right ) + \frac{1}{2} \, B a^{3} d^{2} x^{2}{\rm sign}\left (b x + a\right ) + \frac{3}{2} \, A a^{2} b d^{2} x^{2}{\rm sign}\left (b x + a\right ) + \frac{1}{3} \, A a^{3} x^{3} e^{2}{\rm sign}\left (b x + a\right ) + A a^{3} d x^{2} e{\rm sign}\left (b x + a\right ) + A a^{3} d^{2} x{\rm sign}\left (b x + a\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(B*x + A)*(e*x + d)^2,x, algorithm="giac")
[Out]